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GATE CSE 2015 | Set 3 | Question: 36

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Two hosts are connected via a packet switch with $10^7$ bits per second links. Each link has a propagation delay of $20$ microseconds. The switch begins forwarding a packet $35$ microseconds after it receives the same. If $10000$ bits of data are to be transmitted between the two hosts using a packet size of $5000$ bits, the time elapsed between the transmission of the first bit of data and the reception of the last bit of the data in microseconds is ______.

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There are two packets of 5000bits each, Transmission time = 500$\mu s$

First packet arrives after $= {500}{}{}\mu s+20\mu s$  $ +   { 500}{}{}\mu s+20\mu s$ $+35\mu s$ $= {1075}{}{}\mu s$

Second packet will take same time as first packet but starts from ${}{500}\mu s$ $= {1075}\mu s + {}{500}\mu s$ $= {1575}{}{}\mu s$
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Hope you like my ans i know it's big sort ans are alredy given by other people above

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