Computer Networks - ACE

Question

Comments

1100?

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yes. Please write how?

Answer 1

Suppose first packet is sent at t=0 and lost...next 7 packets will be sent at t=100, 200, ...700(window=8)
now stop at t=800 (window size is 8 and ACK for first packet has not arrived)
ACK for 2nd,3rd,4th packet will be duplicate ACKs, and will arrive at t=900, 1000 and 1100
now,after recieving all 3 duplicate acknowledgements first packet is again re-transmitted at t=1100
ACK will arrive at 1900
Time lost = 1900-800 = 1100

Comments

Here you assumed it to be first packet for simplicity, but it can be any other packet. rt?

And we are required to calculate the time lost due to 3 duplicate ack. right?

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Can I say it like : we are required to find time lost due to 1 packet loss and we come to know whether packet is lost only after we receive 3 duplicate Ack's.

So, time lost = 1RTT + 3 ACK's = 800 + 300 = 1100

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yea u can take any packet i just tried to make it simple..