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Recent questions tagged hyperbola
0
votes
1
answer
1
ISI2014-DCG-59
The equation $5x^2+9y^2+10x-36y-4=0$ represents an ellipse with the coordinates of foci being $(\pm3,0)$ a hyperbola with the coordinates of foci being $(\pm3,0)$ an ellipse with the coordinates of foci being $(\pm2,0)$ a hyperbola with the coordinates of foci being $(\pm2,0)$
The equation $5x^2+9y^2+10x-36y-4=0$ representsan ellipse with the coordinates of foci being $(\pm3,0)$a hyperbola with the coordinates of foci being $(\pm3,0)$an ellipse...
Arjun
309
views
Arjun
asked
Sep 23, 2019
Others
isi2014-dcg
hyperbola
ellipse
non-gate
+
–
0
votes
1
answer
2
ISI2015-DCG-44
If the distance between the foci of a hyperbola is $16$ and its eccentricity is $\sqrt{2}$, then the equation of the hyperbola is $y^2-x^2=32$ $x^2-y^2=16$ $y^2-x^2=16$ $x^2-y^2=32$
If the distance between the foci of a hyperbola is $16$ and its eccentricity is $\sqrt{2}$, then the equation of the hyperbola is$y^2-x^2=32$$x^2-y^2=16$$y^2-x^2=16$$x^2-...
gatecse
288
views
gatecse
asked
Sep 18, 2019
Others
isi2015-dcg
geometry
hyperbola
+
–
0
votes
1
answer
3
ISI2016-DCG-44
If the distance between the foci of a hyperbola is $16$ and its eccentricity is $\sqrt{2},$ then the equation of the hyperbola is $y^{2}-x^{2}=32$ $x^{2}-y^{2}=16$ $y^{2}-x^{2}=16$ $x^{2}-y^{2}=32$
If the distance between the foci of a hyperbola is $16$ and its eccentricity is $\sqrt{2},$ then the equation of the hyperbola is$y^{2}-x^{2}=32$$x^{2}-y^{2}=16$$y^{2}-x^...
gatecse
266
views
gatecse
asked
Sep 18, 2019
Geometry
isi2016-dcg
hyperbola
curves
non-gate
+
–
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