Register

segmentation with paging

2,402 views

2 Answers

1 1 vote
number of pages in segment table=512=$2^9$

number of entries in page table of segment table=number of pages in segment table=$2^9$

size of each entry in page table=2 words

total size of page table of segment table=number of entries*size of each entry=$2^9*2=2^{10}=1 K words$
Voting & Accepting an answer helps improve the community
← Previous · Hashing problem - pl...Next → · C programming
← Previous in category · Priority SchedulingNext in category → · External fragmentati...
Position:
Show:

Related questions

3 3 votes
2 2 answers
152
152 views
GO Classes asked Aug 11
152 views
GO Classes DPP | GATE CS | Operating System | Segmentation with Paging
Assume a task is divided into $8$ equal-sized segments, and page tables have $4$ entries.Thus, the system has a combination of segmentation and paging.Assume also that th...
0 0 votes
0 0 answers
1.5k
1.5k views
A_i_$_h asked Dec 8, 2017
1,534 views
segmentation with paging
For each of the four processes P1, P2, P3 and P4. The total size in kilobytes (KB) and the number of segments are given below.ProcessTotal size (in KB)Number of segmentsP...
1 1 vote
0 0 answers
908
908 views
Tuhin Dutta asked Nov 8, 2017
908 views
GATE-2006-IT-56: Doubt in Segmentation with Paging part.
https://gateoverflow.in/3600/gate2006-it-56Why is only 1 Page Table considered for 4 Segment Table entries in the selected best answer?
1 1 vote
1 1 answer
1.0k
1.0k views
just_bhavana asked Jul 16, 2017
1,016 views
Paging with segmentation
Consider a system with segmented paging architecture where logical address space and physical address space is 216 B. The LAS is divided into 8 equal size pages which are...