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Ace Test Series: Programming & DS - Programming In C

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output is 30

 

*(p+20*j+i)=i*30+j;

for i=0, j=0 , *(p+0)=0 -> a[0][0]

for i=0, j=1, *(p+20)=1 -> a[0][20]

for i=0, j=2, *(p+40) = 2 ->a[1][10]

so, a[6][10]=*( p+6*20+10)  so i = 10, j= 6, so value= 10*30 + 6

a[6][9]=*( p+6*20+9)  so i = 9, j= 6, so value= 9*30 + 6

    printf("%d",a[6][10]-a[6][9]);

a[6][10]= 306

a[6][9]=276

difference 30
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