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option bytes in HLEN

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The value of HLEN of IP packet is 1000 in binary. The number of bytes of options are being carried by this packet __________.

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HLEN = 1000 = $(8)_{10}$

Header length is scaled by a factor of $4$. So, Actual header size $= 8*4 = 32B$ Out of which $20B$ are necessary and remaining $32-20 = 12$ bytes are for options.

So, Ans = $12$
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