96 96 votes The following functional dependencies hold true for the relational schema $R\left \{V,W,X,Y,Z \right \}$:$V \rightarrow W$$VW \rightarrow X$$Y \rightarrow VX$$Y \rightarrow Z$Which of the following is irreducible equivalent for this set of functional dependencies?$V \rightarrow W$$V \rightarrow X$$Y \rightarrow V$$Y \rightarrow Z$$V \rightarrow W$$W \rightarrow X$$Y \rightarrow V$$Y \rightarrow Z$$V \rightarrow W$$V \rightarrow X$$Y \rightarrow V$$Y \rightarrow X$$Y \rightarrow Z$$V \rightarrow W$$W \rightarrow X$$Y \rightarrow V$$Y \rightarrow X$$Y \rightarrow Z$ Databases gatecse-2017-set1 databases database-normalization normal + – Arjun 24.3k views answer comment Share Follow Print See all 9 Comments 9 9 Comments reply Show 6 previous comments nobodysomebody commented Nov 22, 2025 reply Follow flag So when we say V ->Wand VW ->Xinstead of that we can only say V -> X while also keeping in mind that W -> Xcan't be concluded it like saying "only captains approval is required and coach approval and disapproval means nothing"which is wronge (esp in football) 1 1 replyShare js__ commented Dec 11, 2025 reply Follow flag v -> w and vw -> x from these two w can be removed so left with v -> w and v -> xand y -> vx => y -> v and y -> x y -> vv -> x y -> xfrom these 3 y -> x can be eliminated 1 1 replyShare vidhiparimal01 commented Dec 19, 2025 reply Follow flag helpful to understand 1 1 replyShare Please log in or register to add a comment.
Best answer 90 90 votes In option $B$ and option $D$ there is a dependency $W\to X$ which is not implied by the question and hence they are definitely wrong. Now in option $C)$ $Y\to X$ can be removed as it can be implied as $Y\to V$ and $V\to X$. Hence, option (A) is correct. sriv_shubham answered Feb 14, 2017 • edited Jun 22, 2018 by Milicevic3306 sriv_shubham comment Share Follow See all 6 Comments 6 6 Comments reply Show 3 previous comments Radha mohan commented Jun 25, 2018 reply Follow flag i don't think your 1st argument is correct "dependency W−>X which is not implied by the question" because then in option (a) v->x is present then it should not also be correct. 1 1 replyShare MiNiPanda commented Aug 25, 2018 reply Follow flag The problem is in reducing VW->X to W->X OR V->X. From the original set of FD's we calculate V+ and W+ We get V+={VWX} and W+={W}. If we consider option B V→ W W → X Y → V Y → Z then we get W+={WX} and if we consider option A V→ W V → X Y → V Y → Z then W+={W} which is maintained. So we should go for option A. 20 20 replyShare Pushkar_Singh 1 commented Dec 10, 2025 reply Follow flag yep 0 0 replyShare Please log in or register to add a comment.
28 28 votes so, A is the ans. 2018 answered Mar 5, 2017 2018 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes COMMENT BELOW IF YOU HAVE ANY DOUBT akshay_123 answered May 31 akshay_123 comment Share Follow 0 reply Please log in or register to add a comment.