Programmming

Question

int main(){

int a =5;
printf("%d %d %d %d %d ",a++,a--,++a,--a,a);

}

Output is "4 5 5 5 5". How????

Comments

this is compiler dependent right?

---

I think 45545 be answer

---

For all these types of questions which are anyway not relevant for GATE

https://gateoverflow.in/62411/undefined-behaviour-in-c

---

thanks for clearing doubt sir

Answer 1

It is compiler dependent in C.Order of evaluation of arguments of a function is not guaranteed  in C and C++.The order of evaluation of function arguments is unspecified because allowing the compiler to re-order the evaluation of the operands adds more room for optimization.

Bjarne Stroustrup also says it explicitly in "The C++ Programming Language" 3rd edition section 6.2.2, with some reasoning:-

"Better code can be generated in the absence of restrictions on expression evaluation order.".

Answer 2

According to turboo c++ compile

save it as .C extension the Answer is

45545