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+11 votes
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The smallest integer that can be represented by an 8-bit number in 2's complement form is

  1. -256
  2. -128
  3.  -127
  4. 0
asked in Digital Logic by Veteran (346k points)
edited ago by | 2.2k views

2 Answers

+21 votes
Best answer

Range of 2's compliment no = > (- 2n-1 )to + (2n-1 - 1 )

Here n = No of bits = 8.

So minimum no = -2 ^ 7 = (B) -128

answered by Veteran (49.5k points)
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+2 votes
answer - B
answered by Boss (9.3k points)


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