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Suppose that N ethernet stations, all trying to send at the same time, require N/2 slot times to sort out who transmits next. Assuming the average packet size is 5 slot times, express the utilization of ethernet as a function of N

a. 5/(N+10)
b. 10/(10+N)
c 10/N
d. 10/(5+N)

1 Answer

7 7 votes

Here : 

Polling Time = N/2

Polling time is time taken to select which station will transmit next. 

Propogation time is Not given so neglect it.

Now , 

Utilization= (Transmission Time)/(Transmission Time + Polling Time)

= 5/(5+N/2)

=10/(10+N)

So Option B

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