edited by
342 views

1 Answer

Best answer
1 votes
1 votes
A is the answer language 1 and 2 both are regular as x belongs to (0+1)* so it will contain all the strings possible on 0 and 1 which is regular.
In the third language the |x| is limited so it cannot generate all the strings and we also have to match the w with wr which we cant do with it dfa so it is not regular.
selected by

Related questions

2.7k
views
1 answers
0 votes
shekhar chauhan asked Jun 6, 2016
2,688 views
Regular grammars can only describe regular languages, why reverse is not true .What should be the most appropriate Reason ? Explain with in few Lines .If possible give an exp too.
318
views
1 answers
1 votes
1.4k
views
1 answers
0 votes
Garrett McClure asked Sep 7, 2017
1,440 views
Find a DFA for the following language on Σ = {0, 1}L = {w : the value of w, interpreted as a binary representation of an integer is zero modulo five}. For example, 0101 and 1111, ... 5) mod 5, (2n + 1) mod 5 = [(2n mod 5) + 1] mod 5.
987
views
1 answers
0 votes
shekhar chauhan asked Jun 8, 2016
987 views
Write a Grammar which is a not type -3 Grammar, from the Language L over alphabets {a ,b} which contains ab as a Sub-string. Explain the procedure with Example .