2 2 votes (a+b)*a(a+b)*(a+b)* b * a b * a (a + b)* (a + b)* a b* a b* b * a (a + b)* a b* All are generating same language. Theory of Computation theory-of-computation regular-expression + – Desert_Warrior 3.3k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
2 2 votes Look at R.E. 1 & 2,3,4 In R.E. 2 ,it cannot produce 'a'. So Regular expression 1 will never generate same language as of others Rohit01 answered Aug 23, 2015 Rohit01 comment Share Follow 0 reply Please log in or register to add a comment.
2 2 votes this the very simple . start with the minimum strings that can be made . starting with first string every language with a as a substring will be accepted. and minimum string will be a .but every other language minimum string will be aa. hence 1 is not like other. Tendua answered Aug 23, 2015 Tendua comment Share Follow 0 reply Please log in or register to add a comment.
1 1 vote 2,3 and 4 are generating same language. 1 is different. :) Himanshu1 answered Oct 29, 2015 Himanshu1 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes R.E. 1(min string is "a") is different from others R.E.2,3,4(min string is "aa" ) but R.E.1 can also generate "aa", so Ans is 5.All are generating same language, and the Language is having atleast 2 a’s. shaktipratap answered Apr 5, 2019 shaktipratap comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes string generated by 1 contain atleast one "a" while 2,3,4 must contain atleast two "a" Shailendra_ answered Sep 7, 2019 Shailendra_ comment Share Follow 0 reply Please log in or register to add a comment.