Pointers and function

Question

Comments

it will print 2 and then give runtime error, because after function foo() will teriminate, 'j' will become dead. but

printf("%d", *p) is trying to print 'j' which is no more alive.

option D should be correct.

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i think 2,2 should be answer

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@Red_devil

no,
2,2 can't be answer because printf("%d", *p) is called after activation record of foo() has been popped out, making all its static variables dead.

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GZB bhai @Joshi

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I also chose option D but given key was A

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@joshi

before poping , we have stored the address of "j" in main function, so , poping "foo" will matter ?

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but value at that address is no more alive..

actually it totally depend on compiler, what it do to the value after the activation record is popped out

Answer 1

The correct answer is 2,2

Even though activation record deletion deletes j variable, since we've already stored the memory location (address of j) in p variable of main, it's accessible even after deletion of activation record. Suggestions/improvements are welcomed

Answer 2

it should give compilation  error because function "foo" is not declared before its use.
 so option c is correct