2 2 votes Suppose blocks hold either three records, or Ten (Key,pointer) pairs. As a function of n, the number of records, for dense index.How many levels of index as is appropriate until the final level of index has only one block? a) n/3^n b) log3n c) n/4^n d)log10n Databases indexing + – Kajal K 1.8k views answer comment Share Follow Print See all 4 Comments 4 4 Comments reply saxena0612 commented Nov 23, 2017 reply Follow flag I am getting d)log10n . 0 0 replyShare Kajal K commented Nov 23, 2017 reply Follow flag how? Explain 0 0 replyShare saxena0612 commented Nov 23, 2017 reply Follow flag For dense index at first level N entries require N/10 Blocks. Second level we have N/10 entries require N/100 Blocks . . . Sum=N/10+N/100+N/1000...........N/10k 10k=N K=log10N 2 2 replyShare abhishek tiwary commented Nov 23, 2017 reply Follow flag i am also getting d 0 0 replyShare Please log in or register to add a comment.