Data rate per connection in transport Layer

Question

In a network that has a maximum TPDU size of $128$ bytes, a maximum TPDU lifetime of $30$ sec, and an $8- bit$ sequence number, what is the maximum data rate per connection?

My attempt: in $30 sec$ we can identify $256 bytes$ because sequence number is given to each byte of TCP rather than each segment. so data rate should be $68.26bps$ .

But in given answer they are giving sequence number to each segment and thus calculating the data rate as $256*128*8$ bits in $30 sec$ or $8.7Kbps$.

Comments

8 bit for sequence number

So, total how many sequence number possible?

$2^{8}$

Now, for $2^{8}$ numbers total bytes consumed $2^{8}\times 128B$

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that's what I want to say "sequence number is per byte not for segment" if we say sequence number of a segment is $100$ it means $100$ is sequence number of first byte in the payload field of this segment.and if segment size is $50$ then sequence number of next segment will be $150$.

TCP is byte strem protocol and sequence number is given  irrepective of segment size.

@srestha, now tell me where I am doing wrong.because everwhere answer given is with respect to the segment size i.e. $128B$.

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where w.r.t segment size?

it is in bps

So, w.r.t. bits it is calculated

Answer 1

In 30 sec we can identify $2^8$ B ( because in TCP sequence number is given to each Byte). So data rate should be 68.26 bits/sec. 

Thank You @reena_kandari ji.

Comments

yes, thank you!!