Continous_Probability

Question

Consider the two independent random variable X and Y having probability density functions uniform in the interval [0,1]
 The probability that X+Y>1.5 :

$a)\frac{1}{4}$     $b)\frac{1}{2}$
$c)\frac{1}{3}$     $d)\frac{3}{8}$
$e)None \ of \ these$

Comments

he calculated y > 1.5 -x

then using this he set the shaded portion

when x =0, y = 1.5 which is not in the region its only upto x = 0.5 y =1

then, when x = 1 y = 0.5

Hence by this way he decided boundries.

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if x = 0.8 and y = 0.7 and vice versa then what?

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@Shubhanshu

every point which satisfy x+y>1.5 is present in shaded region.