1 votes 1 votes Operating System operating-system + – Pawan Kumar 2 asked Dec 29, 2017 Pawan Kumar 2 431 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Ajay Jadhav commented Dec 29, 2017 reply Follow Share 24GB 1 votes 1 votes hs_yadav commented Dec 29, 2017 reply Follow Share logical address space would bbe divided... 32 16 16 frame/page size 64-bit system means 64-address line...Main Memory size is 264 ..264-16 no of frames... then in ideal case PTE would be equal to 48 bits or 6 bytes....total size of outer pagetable is 232*6:- 24GB ?? 1 votes 1 votes Pawan Kumar 2 commented Dec 29, 2017 reply Follow Share hs_yadav Sir can you plz elaborate how this PTE is calculated and why this "ideal" is used ?thank u 0 votes 0 votes Ashwin Kulkarni commented Dec 29, 2017 reply Follow Share @Pawan Kumar, PTE = frame number = bits use to represent all the frames. (But remember it is not equal to always frame number, there might be some more bits such as reference bit, dirty page bit, etc present, but don't worry about that here, that would explicitly mentioned in the question) So, PTE = frame number no of frames = MM size/PS = 264 /216 = hence total frames = 2^48 (bits req =48= frame number = PTE) 1 votes 1 votes Pawan Kumar 2 commented Dec 29, 2017 reply Follow Share got it sir thank you everyone 1 votes 1 votes Please log in or register to add a comment.
1 votes 1 votes See Physical address=f+d=64 bits Logical address=P1+P2 +d=64 Here P1=32,P2=16 From above d=16 bits =page size bits Now f=64-16=48 bits Now outer page table size=2^32*48bits =2^32*6 bytes=24 GB Amit puri answered Dec 29, 2017 Amit puri comment Share Follow See all 0 reply Please log in or register to add a comment.