DOUBT ON FUNCTION DECLARATION WITHIN A FUNCTION IN C

Question

#include <stdio.h>
int yellow();
int main()
{  
    int hello();
    yellow();
    printf("%d",hello());

    return 0;
}

int yellow(){ hello();    
}

int hello()
{printf("hello hello ");
return 1;
}

HERE I DECLARED THE FUNCTION hello() within my main function but its visible outside the main function also i expected this to give me a compilation error as the hello() is called inside yellow() but hello() is not inside the scope of yellow() but it compiles fine and outputs hello hello hello hello 1 ....are local delaration of functions globally scoped in C ??

Comments

thanks a lot  @MiNiPanda so by default every function is extern so is visible throughout the program there is no such concept as local functions in C 

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Yes..this thing i just came to know the day before you posted this :P

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https://gateoverflow.in/132630/extern-variable-in-c read this post its good about the same concept 

Answer 1

it is giving  compiler error since  hello() was not initialized/declared before using. 

Comments

Declaration before using is mandatory. Here he is asking about the visibility of the function which is present in some different block.

His snippet is working fine.