0 0 votes Operating System + – pradeepdeepu 486 views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Ashwin Kulkarni commented Jan 29, 2018 reply Follow flag Given that physical memory is 128 KW and divided into $2^{14}$ frames. Hence Page size or frame size = $2^{13}$ Hence offset bits will be $13$ Now in two level paging each page has $2^{12}$ hence 12 bits each Hence total length of LAS $= 12+12+13 = 37$ bits 0 0 replyShare pradeepdeepu commented Jan 30, 2018 reply Follow flag They have given each page table is divided into 2^12 pages but not each page is divided into 2^12 entries. For outer level 12 bits is ok, but for inner level how can we take 12 ,we have to take the number of entries each page was divided? 0 0 replyShare Please log in or register to add a comment.