Increment Operator in C language

Question

Q) What is the output of the following C Program fragment

#include<stdio.h>

int main()

{

int a = 4, b = 3;

printf("%d",a+++++b);

return 0;

}

 

A) 7      B) 8             C) 9               D) Error

Answer 1

If there is no space between the post increment and preincrement operators, then there will be an error. Else it will run as usual 

Comments

Please see the source of question

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@Sayan Bose,While executing the code the error which popped up was
"lvalue" required.

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Yes if all the + are written one after the other(without any space) then compilation error is "Lvalue required" but I am not able to understand what a+++++b implies i.e. whether it has any significant meaning in programming.

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@Sayan Bose,A slight modification. The code will work fine in the following manner:-

printf("%d",(a++)+(++b));

Parentheses set a priority. Executing this way the answer is 8.

Answer 2

OPTION: B is correct.

The output of this program will be 8 as the unary increment operator works right to left so in the statement a+++++b it will first increment b to 4 and will then perform addition and after that will update a.

 

Initially, a=4, b=3;

in a++ + ++b, b will be 4 and a will remain 4, so addition will be 4+4=8. So the output will be 8.

After printf the value of a will become 5.