2NF Question.

Question

Given a table $R(ABCDEF)$

$ABC -> D$

$ABD -> E$

$CD   ->  F$

$CDF -> B$

$BF    -> D$

It's candidate keys are $ABC, ACD.$

 So while checking for $2NF$, Can I say that $ABD -> E$ is not partially dependent because $ABD$ as a whole is not a part of candidate key even though $AB$ is a part of candidate key.

Comments

ACD is a key

CD-> F has partial dependency

Answer 1

Yes you are right whole is the part of key. Here ABD is not part of key . So it have no partial dependencyv.