c program

Question

#include<stdio.h>
int main()

{

  int i=0;

 for(printf(" one\n "); i < 3 &&  printf(" "); i++)

{

         printf("Hi!\n");

}

return 0;

}

Comments

one
  Hi!
 Hi!
 Hi!

---

(space)one

(space)(space)Hi

(space)Hi

(space)Hi

---

how?

can you explain..

---

A for loop is defined as

for(initialization ; Condition ; Increment/Decrement)

{

statements

}

Initialization is done only once. Then condition is checked.

And then, statement execution -> Increment / Decrement -> Condition check is carried out in a loop fashion.

Try it now :)

Also, if you are confused how  i < 3 &&  printf(" ") works. printf function returns the number of characters it printed successfully. Note that you are printing one character (space) here.

---

@gaurav

Nice explained.

My doubt is in intialization part of loop -> printf should return 3 as it contains 'one' so variable 'I' should be initialised to 3 than 0.

Please suggest

Thanks

---

printf(" one\n ") will return 6. As there are 6 characters between double quotes. Characters include not only alphabets but also space, newline, punctuation marks, etc. Note that \n is considered as one char as it represents a new line. Also, there is space before and after the string.

The value returned by printf is not assigned to i. Hence i will still be 0 (as initialized before entering loop)

---

@gauravkc
Thank you!
Nice explanation.!!!!