0 0 votes https://gateoverflow.in/8283/gate2015-1-35 how x+3 and *(x+3) printing the same output Programming in C usergate2015 usermod + – himgta 600 views answer comment Share Follow Print See all 2 Comments 2 2 Comments reply Shaik Masthan commented Sep 5, 2018 reply Follow flag even though the output look same, they are really different it is a two dimensional array. ===> collection of 1-D arrays x ===> 0th 1-D x+3 ==> 4th 1-D *(x+3) = *(x+3) + 0 ====> 4th 1-D, 0th element Address But the printing was same due to memory address of 4th 1-D = memory address of 4th 1-D, 0th element Address. 1 1 replyShare himgta commented Sep 5, 2018 reply Follow flag i thought that x+3 will give the address of the pointer that is pointing to 4th 1-D array.....106(assumed) 0 0 replyShare Please log in or register to add a comment.
0 0 votes X+3 is the address of 4th 1-d array, while. ( *(x+3) +0) is the address of first element of the 4th 1-d array, they both refers to the same address. himanshu19 answered Sep 6, 2018 himanshu19 comment Share Follow 0 reply Please log in or register to add a comment.
