Here, answer is yes. There is error in This message. Error is in bit $6$.

How to calculate it? First of all reverse given input to get it in correct position from $1$ to $7$.

$0110001$

$\text{Bit-1, Bit-2 & Bit-4}$ are partity bits.

Calculating position of error $\Rightarrow$

$\text{$\large c_4 c_2 c_1$}$

$\text{1 1 0}$

Here, $c4 = \text{bit}4\oplus \text{bit}5 \oplus \text{bit}6 \oplus \text{bit}7=0\oplus 0\oplus 0\oplus 1=1$

$\text{ (Taking Even parity )}$

$c2 = \text{bit}2\oplus \text{bit}3\oplus \text{bit}6\oplus \text{bit}7=1\oplus 1\oplus 0\oplus 1=1$

$c1= \text{bit}1\oplus \text{bit}3\oplus \text{bit}5\oplus \text{bit}7=0\oplus 1\oplus 0\oplus 1=0$

**Reference: **$\Rightarrow$ https://en.wikipedia.org/wiki/Hamming%287,4%29

When you correct bit $6$.

You get a message as $0110011$.

If you calculate $\large c_4,c_2,c_1$ all will be $0$ now!