0 0 votes a system has 13 bit instruction and supports one address and zero address instruction.if there are 32 one address instructions,how many zero address instructions are supported by the processor (assume 128-word memory) 1)2048 2)1024 3)3072 4)4096 CO & Architecture co-and-architecture cpu-organization zero-address-instructions + – altamash 814 views answer comment Share Follow Print See all 4 Comments 4 4 Comments reply Shubhgupta commented Oct 15, 2018 reply Follow flag $2^{13} - 32*2^{7} = 4096$ Option D. 0 0 replyShare Magma commented Oct 15, 2018 i edited by Magma Oct 15, 2018 reply Follow flag Shubhgupta How you do that ?...explain me please !! 0 0 replyShare Shubhgupta commented Oct 15, 2018 reply Follow flag No. of possible instruction encoding =$2^{13}$ No. of encoding taken by one-address instructions =$32 * 2^{7}$ (because 128 memory word size is given) So, no. of possible zero-address instructions =$2^{13} - 32 * 2^{7}$ = 4096 I think in question it is 32 one address instruction. 1 1 replyShare Magma commented Oct 15, 2018 reply Follow flag Thanks 0 0 replyShare Please log in or register to add a comment.
