MultiDimensional Array

Question

What is the Output of following Array ? 

A. 8 10

B. 10 8

C. 10 2

D. 8 1

E. Garbage value

Comments

option A...

what is the problem you are facing while answering?

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I got the answer right though i am confused at q = (int*)arr part how *q is giving 10 as arr is 3 dimensional please clear me at this point

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check the answer https://gateoverflow.in/254355/test-series-question

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Brother say in question something like int q = (int **)arr would have been written then q value would be 10 right ?

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you declared q as integer pointer,===> single pointer

(int **)arr is a double pointer, then how can you assign it to q ?

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No brother that's not what i meant i said that suppose i declared an identifier as ' int q ' then what will be the value of

q = (int**)arr           // because (int*)arr will be address of 1st element of 1d array so will (int**)arr will fetch the value ?

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because (int*)arr will be address of 1st element of 1d array so will (int**)arr will fetch the value ?

(int **) means you are making it as double pointer.

Brother, understood the difference between

(int **)arr and **arr

(int **)arr -------- making it to the double pointer.

**arr ---- dereferencing the double pointer

 

will (int**)arr will fetch the value ?

* (int *)arr ----> will fetch the value

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can u explain??? how output is8,10

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Note that index starts with 0.

p = &a[1][1][1]  ===> p points to the 1st index element of 1st index 1-D of 1st index  2-D  ==> *p = 8

q = (int *) a ===> q points to 0th index element of 0th index 1-D of 0th index  2-D  ===> *q = 10

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What happens if I declare
int **q = (int **)a;
Please can anyone explain this?I think it's showing segmentation fault.But why? Please anyone could tell?

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Why are we converting arr to single pointer?

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check the link shared by me.

for your second doubt, in the question, it asked like that so we did , but not by us.