Transaction Query

Question

Consider the following schedules:

S1: r1(A); r1(B); w1(C); w2(D); w1(A); w2(A); r1(D);
S2: r1(A); r1(B); r1(C); r1(D); w1(A); w2(B); w3(C); w4(D)

Which of the following option is correct?

A) S1 has blind write S2 does not

B) S2 has blind write S1 does not

C) Both schedules are conflict serializable

D) None of the above

Correct me if I am wrong but I think S1 and S2 both have blind writes?

Comments

D ) S1 and S2 both has blind write

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My answer was D too but the answer given is A. I think it's wrong

Answer 1

Definition of Blind Write: When a transaction  Writes a Data Item Without Reading It, That is called a Blind Write.

So the Answer is D.

Anything Else is False.