made easy 2019

Question

I AM GETTING 28%

WITH TLB= 140ns

WITHOUT TLB= 500ns

i havent considered memory access time, just address translation time is cosidered!

am i right??

Comments

i dont what they have done??

i thought if not 28% then answer could be 64%

but how 36%, am not getting it!

answer might be wrong!!

then what can be the correct answer??

---

lets wait for someone to clarify

---

I THINK ANSWER IS CORRECT

Answer 1

36 percent is correct.

The time taken without TLB will be $2 \times T_m$, as once we'll have to look for the correct address in the memory and one more access for actually accessing that value.

The time taken with TLB will be $T_{\text{tlb} + T_m}$ as we'll get the address from the TLB and then we can access the memory to find the relevant data.

Going by that, the respective times are 1000 ns and 640 ns.

The speedup will be given by: $\frac{\text{Old Value - New Value}}{\text{Old Value}} \times 100$ which will be $\frac{1000-640}{1000} \times 100$ which is 36 %.

Comments

but speed up is old value/new value

right??