Gateforum Test Series: Digital Logic - Floating Point Representation

Question

Comments

b?

---

Yes, please elaborate

---

in normalized form, there is a explicit 1 before mantissa, which is not the case for un-normalised number. so find out binary representation and shift the decimal before 1st 1, adjust the exponent accordingly. try it as i said, you will get b.

---

okk but if noting is specify then we used which representation

1.M or 0.M

Answer 1

2.25  = 10.01 * 2^0 = 0.1001 * 2^2

In un-normalized version , number is represented as  (-1)^s 0.M x 2^(E-63)

here M = 1001

Now E-63 = 2 => E = 65.

And, s=1 , since number is Negative.

 

So the representation would be ,

1 100100000000000000000000 1000001

where s=1

M=100100000000000000000000

and E-63 which is 65 is 1000001,

from extreme right ,  make groups of 4.

After making groups , one can easily see it is , C8000041

Comments

Perfect brother (Y)

---

Nice thank you. It was an easy stuff but always confused me.