0 0 votes .. an getting 0.00010650 Operating System operating-system paging translation-lookaside-buffer raman-classes-test-series numerical-answers + – Gate Fever 835 views answer comment Share Follow Print See all 5 Comments 5 5 Comments reply Soumya Tiwari commented Nov 13, 2018 reply Follow flag I'm also getting same- 10^-9*(.95(1+100)+0.05(1+10+2*100)) They have taken only one memory access while calculating when miss occurs.I'm not getting why? 0 0 replyShare adarsh_1997 commented Nov 13, 2018 reply Follow flag please mention test series name. 1 1 replyShare aambazinga commented Nov 13, 2018 reply Follow flag i think they are right.. why taking 2 memory access after miss, when they have already given 10ns of overhead for TLB miss... so effective access time will be...1ns(1ns+100ns+0.05*10ns).... converting it into ms gives 0.000101.5ms 0 0 replyShare garimanand commented Nov 13, 2018 reply Follow flag m getting 0.00010150 ms 0 0 replyShare Gate Fever commented Nov 14, 2018 reply Follow flag so this is the correct EAT EAT= 0.95*1+ 0.05*11+100 ns = 0.0001050 ms since they have given if miss is recorded then overhead is 10ns 0 0 replyShare Please log in or register to add a comment.
