+1 vote
124 views
Find the value of $\lambda$ such that function f(x) is valid probability density function

$f(x)=\lambda (x-1)(2-x)$ for $1 \leq x \leq 2$

$=0$ otherwise

My $\lambda$ is coming to be $- \frac{6}{5}$

Am I correct?
| 124 views
0
I m getting 6...
0
Yeah 6 is given in the key.
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Integrate from 1 to 2 which evaluates to 1 ,Therefore lambda=6
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akash.dinkar12 plzz add answer .. i am also getting diff.

+2

see this....

+1
I am getting 6...i think you have done some calculation mistake.
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yes..
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Yeah I was doing calculation mistake. Answer is 6.