1,468 views

2 Answers

Best answer
1 1 vote

In given transactionsn, we can make polly graph by using First Read and Last Write, then merge both of them.

edited by
0 0 votes
If T1 first read then it also first write to removing cycle from precedence graph but that not possible so given schedule not view
Position:
Show:

Related questions

2 2 votes
0 0 answers
727
727 views
ashish pal asked Jan 26, 2018
727 views
Answer given is 24 which is the no. of serial schedules possible, but my doubt is since no two transactions share same variables then all the schedules possible will be c...
1 1 vote
2 2 answers
1.4k
1.4k views
Durgesh Singh asked Sep 30, 2017
1,368 views
Consider a Serial Schedule given-T1T2T3w1(A) w1(B) r2(A) w2(B) r3(A) w3(B) How many schedules which are view equivalent to above schedule?How many schedules whic...
1 1 vote
1 1 answer
527
527 views
Ravi prakash pandey asked Apr 10, 2018
527 views
how view serializability ensures serial schedule??i mean in view we leave many conflict like RW,WW,......we only talks about WR conflict and intial read and final write.t...
2 2 votes
1 1 answer
819
819 views
Abhijeet_Kumar asked Dec 8, 2017
819 views
Consider two transactions $T_{1}$ and $T_{2}$ are given as follows$\mathrm{T}_{1}: \mathrm{R}(\mathrm{A}) \mathrm{W}(\mathrm{A}) \mathrm{R}(\mathrm{B}) \mathrm{W}(\mathrm...