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in Computer Networks by (25 points) | 73 views
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$3599=59*61$

$\phi(n)=(59-1)*(61-1)=3480$

$d*e\equiv (1)mod(3480)$

After solving a lot

$d = 3031$
0
i got d=449. after that how did we get 3031 i need to understand that?
0
(449*31)3480 is not 1
0
its d= -449 so it will be 3480-449= 3031
0

multiplicative inverse

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