Register

limit

• recategorized by
529 views

1 Answer

Best answer
2 2 votes
answer = option D

at large value of $x$ the value of $\sin x$ will always be between $-1,1$ while $x$ will keep growing which is a denominator hence, $$\lim_{x \rightarrow \infty} \frac{\sin x}{x} = 0$$
• selected by
Voting & Accepting an answer helps improve the community
← Previous · LL(1)GrammarNext → · Limit
← Previous in category · What is the maximum ...Next in category → · Limit
Position:
Show:

Related questions

2 2 votes
1 1 answer
162
162 views
GO Classes asked May 11
162 views
GO Classes DPP | GATE CS, DA | Calculus & Optimization | Limit Laws
Which of the following statements is/are TRUE?If $\lim_{x\to a} f(x)$ exists and $\lim_{x\to a} g(x)$ exists, then $\lim_{x\to a} f(g(x))$ must exist. If $\lim_{x\to a} f...
2 2 votes
1 1 answer
465
465 views
GO Classes asked Dec 11, 2025
465 views
GO Classes DPP | CALCULUS & OPTIMIZATION |LIMIT
Estimate the value of the following limit:$$\lim _{x \rightarrow 2} g(x)$$where the function $g(x)$ is defined as:$$g(x)= \begin{cases}\frac{x^2+4 x-12}{x^2-2 x} & \text ...
1 1 vote
2 2 answers
403
403 views
GO Classes asked Dec 9, 2025
403 views
GO Classes DPP | CALCULUS & OPTIMIZATION |LIMIT
$\text { Estimate the value of the following limit. }\\$$$\lim _{x \rightarrow 2} \frac{x^2+4 x-12}{x^2-2 x}$$