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WHY ONLY OPTION D IS CORRECT A AND B ARE ALSO

$(A)YZ\rightarrow P$

$B_{2}C_{2}\rightarrow D_{1}$

$B_{2}C_{2}\rightarrow D_{4}$

Not possible.

$(B)Y\rightarrow X$

$B_{2}\rightarrow A_{2}$

$B_{2}\rightarrow A_{3}$

Not possible.

$(D)ZP\rightarrow Q$

$C_{1}D_{1}\rightarrow E_{1}$

$C_{1}D_{2}\rightarrow E_{1}$

$C_{2}D_{1}\rightarrow E_{2}$

$C_{2}D_{4}\rightarrow E_{2}$

It is possible for given instances.
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