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If all the natural numbers starting from $1$ are written side by side $(123456789….),$ then find the $100^{th}$digit of this series

$(A) 2$                $(B) 3$              $(C) 0$           $(D) 5$               $(E)$None of these
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+3
1 to 9 = 9 digits

10 = 2 digits

11-50=80 digits

51 to 54= 8 digits

'5' of '55' would be 100th digit.
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D ?
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Thanks

+1 vote
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