ME Testseries

Question

Comments

7mss

---

7 mss sorry I misread the question

---

@Manojkumar Susarla how????

---

I am getting 8 MSS

Answer 1

starting from 2 MSS we proceed 2-4-8 after third tranmission we will reach threshold 12 MSS from where additive increase will start

now 12-13-14-15 during 7th transmission we get time out means threshold will be floor(15/2)=7

now start for 8 transmission with intial segment size=2mss

2-4-7-8-9-10 so at the end of 12th transmission answer is 10mss

Comments

Initially will it directly increase it to 12 MSS in fourth transmission ( 2 - 4 - 8 - 12 ) ?

Because in slow start the window doubles , am i correct?

---

it will increase upto 8 mss exponentially then on next transmission we will have we will have four segments acknowledged making sender size to 12 and then additive increase will start