# DH algorithm

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How to calculate such a value:

Please, someone explain because this is not possible on cal….!

1

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=(13^3%11 * 13^3%11 * 13^3%11) %11

=( 8 * 8 * 8)%11

=512%11

=6

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## Related questions

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How to calculate Mod of a big number in RSA Like 5 raise to power 13 mod 77
In RSA Algorithm, we have public key(e,n) and private key(d,n). Sender side we encrypt plain text P as an integer between 0 and n-1 as follows: $P^{e}modn$ and send it. At receiver side, we do the following: $(P^{e}modn)^{d}modn = P^{ed}modn$ ... encrypting the message P we are taking it as as integer between 0 and n-1. So, the P may not be coprime to n. Then how does the algorithm work?