1)transmission time=12000/100*10^6= 120 us
packer reaches at switch=120+10=130us
then from switch to destination=130
so total latency=260us
2)for 3 switches =130*4=520 us(as packet has to go over 4 links)
3)For “cut-through”, a switch needs to only decode the 200 bits before it begins to forward. This takes 2 us. This delay replaces the switch transmit delays in the previous answer for a total delay of one transmit delay + 3 cut through decoding delays + 4 propagation delays = 120+3*2+4*10=166 us