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  1. f(A,B,C,D)=∏M(0,1,3,4,5,7,9,11,12,13,14,15) is a max-term representation of a Boolean function f(A,B,C,D) where A is the MSB and D is the LSB. The equivalent minimized representation of this function is
  1. (A+C¯+D)(A¯+B+D)(A+C¯+D)(A¯+B+D)
  2. AC¯D+A¯BD+A¯BC
  3. A¯CD¯+AB¯CD¯+AB¯C¯D¯
  4. (B+C¯+D)(A+B¯+C¯+D)(A¯+B+C+D)
asked in Digital Logic by Junior (795 points) 1 flag
edited by | 92 views

2 Answers

0 votes

find the equivalent min-term which is m(2,6,8,10) 

A¯B¯CD¯+A¯BCD¯+AB¯C¯D¯+AB¯CD¯

A¯CD¯ + AB¯D¯  (After minimizing)

Now take a=1,b=0,c=0,d=0; and some other values if required

Substitute in the equation above and in the options

In this way i am getting is C .

answered by (13 points)
–1 vote
f(A,B,C,D) = m(0,2,6,8,10) =
A¯B¯CD¯+A¯BCD¯+AB¯C¯D¯+AB¯CD¯ =  A¯CD¯(B+B¯) +AB¯CD¯+AB¯C¯D¯ =   A¯CD¯+AB¯CD¯+AB¯C¯D¯
answered by (9 points)
–1
how can you write max term f(A,B,C,D)= minterm f(A,B,C,D)

the right way is minterm = (maxterm)'

therefore
f(A,B,C,D)=∏M(0,1,3,4,5,7,9,11,12,13,14,15) = [ f(A,B,C,D) = m(0,2,6,8,10) ]'

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