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distribution

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If f(x) is normal distribution with mean 8 and std deviation 1 value of f(x) for x=10 is

1)0.05

2)0.14

3)0.25

4)0.73

1 Answer

Best answer
2 2 votes

The probability density of the normal distribution is:

Here $\mu$= Mean or Expectation of the distribution.

The parameter  ​\sigma  is its standard deviation  with its variance then \sigma ^{2}.

Given \sigma =1 and  \sigma ^{2} =1.
$\mu$= 8 and x=10
After putting value in the function

f(x)=0.0540.

Hence Answer is (1)0.05.
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