0 0 votes How many $1$’s are present in the binary representation of $15\times 256+5\times 16+3$: $8$ $9$ $10$ $11$ Digital Logic ugcnetcse-june2007-paper2 number-system binary-representation + – go_editor 479 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
0 0 votes 15*256+5*16+3 = 3923 3923 = 111101010011 Hence A is the correct answer. vg653 answered Mar 29, 2020 vg653 comment Share Follow 0 reply Please log in or register to add a comment.