aptitude

Question

hariharan is fond of shopping , he took an amount of more than 10 and less than 20 rs, with aform of 1rs coins and 20 paisa coins ...when he come back he had as many 1rs nots as many 20paisa coins and as many 20paisa coin as he originally had one rupiee notes . total was reduced by two third thus he spent ?

Answer 1

Let $x$ is the number of $1Rs$ notes and $y$ is the number of $20$ paisa coins.

The amount he,originally, had , $x + (0.20)y$ 

when he come back after shopping ,then he had, number of $1Rs$ notes is as many as  $20$ paisa coins he originally had, and Number of $20$ paisa coins is as many as $1Rs$ notes,  he originally had .

so amount now he has, $y + (0.20)x$ 

Total amount after shopping is reduced by $\frac{2}{3}$. 

so $y+(0.20)x = \frac{1}{3} (x+0.20y)$

$3y+0.6x=x+0.2y$

$0.4x = 2.8y$ 

$x= 7y$ ------(1)

Hariharan originally took the amount for the shopping was greater than $10Rs$ and less than $20 Rs$

$ 10 < x+(0.20)y < 20$ ----(2)

From (1) and (2) ,we get $ x= 14 , y = 2$ 

So, Total amount, he originally had, $x+0.20y = 14.4$  

Amount left after shopping , $y + 0.20x = 4.8$ 

Amount He spent $= Rs \; 9.6 $