0 votes 0 votes Using ‘RSA’ public key cryptosystem, if $p=3$, $q=11$ and $d=7$, find the value of $e$ and encrypt the number $’19’$ $20, 19$ $33,11$ $3, 28$ $77, 28$ Computer Networks ugcnetcse-oct2020-paper2 computer-networks network-security cryptography + – go_editor asked Nov 20, 2020 • recategorized Nov 27, 2020 by Krithiga2101 go_editor 2.0k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes p=3, q=11 and d=7 n=pxq= 33 ϕ(n)=(p-1)x (q-1) =2x10=20 d.e = 1 mod ϕ(n) 7xe=1 mod 20 or 7e=21 =>e=3 C=P^e mod n C=19^3 mod33 C=28 option C is right ans Sanjay Sharma answered Nov 22, 2020 Sanjay Sharma comment Share Follow See all 0 reply Please log in or register to add a comment.