3 3 votes Given solution of the problem: I was thinking of using this formula, $\eta = \frac{N}{1+2a}$ for this question. What is wrong in using it. Please explain Computer Networks computer-networks sliding-window + – shikharV 6.7k views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
Best answer 4 4 votes You can solve this problem using η=N/1+2a also as follows Transmission time= Frame length/Bandwidth = (512*8)/1024000 = 4msec (as 1Kb data must be taken as 1024 bits) ; Propagation delay = 40msec (given) ; a= 40/4= 10msec N= 7 efficiency =N/(1+2a) = 7/(1+20) =0.33 Throughput=efficiency*bandwidth = 0.33*1024000 = 341.33 Kbps In the solution you have pasted they have used the formula as Efficiency = Amount of data sent/Amount of data that could be sent Efficiency = Amount of data sent / (RTT * Bandwidth) Throughput=Efficiency *Bandwidth ...as bandwidth is both in numerator and denominator both cancels out sarvani videla answered Jan 15, 2016 • selected Jan 15, 2016 by shikharV sarvani videla comment Share Follow See all 4 Comments 4 4 Comments reply shikharV commented Jan 15, 2016 reply Follow flag Thanks! 0 0 replyShare agoh commented Dec 17, 2016 reply Follow flag Is 1 Mbps = 10^6 b/s or 2^20 b/s ? 0 0 replyShare Vishal Goyal commented Jun 20, 2017 reply Follow flag very well explained 0 0 replyShare rohitkolapkar commented Sep 3, 2019 reply Follow flag it is Bandwidth therefore 1Mbps= 10^6 bps 0 0 replyShare Please log in or register to add a comment.
