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In a parallelogram $\text{ABCD, AP}$ and $\text{BP}$ are the angle bisectors of $\angle \text{DAB}$ and $\angle \text{ABC}.$Find $\angle \text{APB} :$

1. $85^{\circ}$
2. $90^{\circ}$
3. $94^{\circ}$
4. $86^{\circ}$

### 1 comment

sum of adjacent angles in //gram is 180 . 1 + 2 + 3 + 4 = 180

angle bisector divede angle in equal parts so 1= 2 and 3 =4

twice of 1 + twice of 3 = 180

1 +3 =90

so angle APB is 90 OPTION B

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