oswal general aptitude

Question

find the last digit of (100008)^12500?

Answer 1

Given: (100008)^12500

Now,

8^1=8

8^2=64

8^3=512

8^4=4096

8^5=32768…..

So, observe the value at units place, it is repeating after 4 numbers. So, now

12500 mod4 =0

So, it is divisible by 4.

Hence, unit place will have 6.

Comments

yes thank you

Answer 2

Is it 6 ?  Divide the exponent by 4 and get the reminder and raise it to the unit digit of the base

Comments

here reminder will be 0 so won't it be like 8^0? because generally we raise the reminder

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yes