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ISI2021-MMA: 20

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$f(x) = x^3 - 2x + 7$
$f'(x) = 3x^2 - 2$

$\therefore 3x^2 - 2 =0$       $x = \pm \sqrt{\frac{2}{3}}$

$max = -\sqrt{\frac{2}{3}}\;\;\;min=\sqrt{\frac{2}{3}}$
So, $f( -\sqrt{\frac{2}{3}})\;\&\; f( \sqrt{\frac{2}{3}})$ both will be positive.

So, there will be only $1$ point where this function will intersect. 
$Ans: \text{B.}\; 1$

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