1 1 vote If $g’ (x) = f(x)$ then $\int x^{3} f(x^{2}) dx$ is given by $x^{2} g(x^{2}) – \int xg(x^{2}) dx + C$ $ \frac{1}{2} x^{2} g(x^{2}) – \int xg(x^{2}) dx + C$ $2x^{2} g(x^{2}) – \int xg(x^{2}) dx + C$ $x^{2} g(x^{2}) – \frac{1}{2} \int xg(x^{2}) dx + C$ Calculus isi2021-mma calculus + – admin 702 views answer comment Share Follow Print 0 reply Please log in or register to add a comment.
1 1 vote option b is correct. https://www.youtube.com/watch?v=bWEH-DCVJU0 KhushiRastogi answered Mar 24, 2023 KhushiRastogi comment Share Follow 0 reply Please log in or register to add a comment.