column major

Question

Consider a three dimensional array A[50][20][30] stored in linear array in column major order . If the base address starts at 1000, the location of A[20][10][10] is ..? (assume first element is stored at A[1][1][1])

Answer 1

procedure will be:

BaseAddress + traverse till A[19] (which is 3D array) then for A[20] traverse till A[20][0][9] then finally traverse A[20][9][10]
therefore the next address will be A[20][10][10]

1000 + (19*(30*20) + 9*20 + 9)*2

NOTE- In question nothing is mentioned about size of element so I've assumed it to be 2 Bytes as address is integer, which is 2 Bytes.

Answer 2

1000 + 19*20*30 + 9*20 + 9

Answer 3

1000+30*30*20+20*20+10